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Informational 12 Bitcoin

test(miniscript): Prove avoidance of stack overflow

Public commit record

What the developer wrote

Authored by Hodlinator

100/100 · Strong
test(miniscript): Prove avoidance of stack overflow

Can be tested through emptying the function body of ~Node() or replacing Clone() implementation with naive version:
```C++
Node<Key> Clone() const
{
std::vector<Node> new_subs;
new_subs.reserve(subs.size());
for (const Node& child : subs) {
new_subs.push_back(child.Clone());
}
return Node{internal::NoDupCheck{}, m_script_ctx, fragment, std::move(new_subs), keys, data, k};
}
```

Co-authored-by: Lőrinc <pap.lorinc@gmail.com>
✓ Specific, descriptive subject✓ Names a concrete action or component✓ Uses a recognizable type or scope✓ Provides detailed explanatory context✓ Mentions testing or verification✓ Names security-relevant behavior explicitly
The short version

What changed, and why it matters

This commit only adds a new automated test to Bitcoin Core. The test builds an extremely deep Miniscript node tree and then exercises its destructor, clone, and move-assignment to confirm they do not overflow the call stack. It is a defensive regression test, not a fix for any currently broken or exploitable behavior.

Recommended action

No action required. This is a test-only addition. Reviewers may verify that the test passes in CI and that the existing ~Node(), Clone(), and move-assignment implementations are indeed non-recursive or tail-call bounded.

Security signals we found

01

Defensive regression test for stack overflow in deep Miniscript trees

02

Tests destructor, clone, and move-assignment stack safety

03

No production code changes

Risk score

Why this scored 12/100

Our methodology →
Potential impact 0/30
Exploitability 0/25
Stealth signal 0/15
Affected reach 0/15
Confidence 8/10
Evidence quality 4/5
Human-validated context

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